In Fig. All the chapter wise questions with solutions to help you to revise the complete CBSE syllabus and score more marks in Your board examinations. Frequently Asked Questions on NCERT Solutions for Class 9 Maths Chapter 6. In figure, ∠PQR = ∠PRQ, then prove that ∠PQS = ∠PRT. The architecture uses lines and angles to design the structure of a building. Thus, ∠SQT = 60°, Ex 6.3 Class 9 Maths Question 5. To access interactive Maths and Science Videos download BYJU’S App and subscribe to YouTube Channel. Ray OR is perpendicular to line PQ. In figure, ∠X = 62°, ∠XYZ = 54°, if YO and ZO are the bisectors of ∠XYZ and ∠XZY respectively of ∆XYZ, find ∠OZY and ∠YOZ. Prove that ROS = ½ (QOS – POS). 4. As they are pair of alternate interior angles. It is also known that alternate interior angles are same and so, QRS +QRT = 180° (As they are a Linear pair). Answers to each question has been solved with Video. From (1) and (2), x = y From the diagram, b+c also forms a straight angle so. If and find ∠BOE and reflex ∠COE. Get clarity on concepts like linear pairs, vertically opposite angles, co-interior angles, alternate interior angles etc. In figure, lines AB and CD intersect at 0. Consider the ΔPQR. Pair of angles (reflex, complementary, supplementary, adjacent, vertical opposite, linear pair). Similarly, ∠PRT + ∠PRQ = 180° …(2) [Linear Pair] 6.29, if AB CD, CD EF and y : z = 3 : 7, find x. 4. 6.31, if PQ ST, PQR = 110° and RST = 130°, find QRS. In figure, lines AB and CD intersect at 0. Basic terms and definitions related to a line segment, ray, collinear points, non-collinear points, intersecting and non-intersecting lines. An angle which is greater than 180° but less than 360° is called a reflex angle.Further, two angles whose sum is 90° are or ∠COE = 180° – 70° = 110° Students can now freely access RD Sharma Class 9 Maths solutions for chapter 8 here. LINES AND ANGLES 91 An acute angle measures between 0° and 90°, whereas a right angle is exactly equal to 90°. Also, ∠AOC + ∠BOE = 70° ∠LBC + ∠ABL = ∠MCB + ∠MCD Since AB is a straight line, Now, in ∆OYZ, we have ∴ ∠APQ = ∠PQR ⇒ ∠QRS = 110° – 50° = 60° Extra Questions for Class 9 Maths Chapter 6 Lines and Angles. ∴ ∠PTR = ∠QTS First, draw two lines BE and CF such that BE ⊥ PQ and CF ⊥ RS. [Linear pair] Draw a line EF parallel to ST through R. 2. ⇒ x = 37° ∴ ∠AED = 35° From (ii), we get If AOC +BOE = 70° and BOD = 40°, find BOE and reflex COE. Thus, ∠BOE = 30° and reflex ∠COE = 250°. Ex 6.2 Class 9 Maths Question 4. While practising the model solutions from this chapter, you will also learn to use the angle sum property of a triangle while solving problems. Required fields are marked *. Question 1. In Fig. ⇒ y = 180° – 90° – 37° = 53° Thus, the required measure of c = 126°. So, PRS = QPR+PQR (According to triangle property). ⇒ ∠SQT = 180° – 75° – 45° = 60° or ∠GEF + 90° = 126° [∵ EF ⊥ CD (given)] In Fig 3.13, lines AB and CD intersect at O. Solution: In ΔABC, ∠A = 50° and the external bisectors of ∠B and ∠C meet at O as shown in figure. Students can also refer to NCERT Solutions for Class 9 Maths Chapter 6 Lines and Angles for better exam preparation and score more marks. Now, as the sum of the interior angles of the triangle. ∵ PQ || RS ⇒ BL || CM In Fig. TQP and PQR) will add up to 180°. Then you can start solving the exercise problems with the help of NCERT Solutions. Ex 6.2 Class 9 Maths Question 1. In figure, if AB || CD, ∠APQ = 50° and ∠PRD = 127°, find x and y. 6.40, X = 62°, XYZ = 54°. These expert faculty solve and provide the NCERT Solution for Class 9, which would help students to solve the problems comfortably. ⇒ ∠YOZ + 27° + 32° = 180° From (1) and (2), we have ⇒ $$\frac { 1 }{ 2 }$$∠P = ∠T Videos related to exercise 6.2 in Hindi and English are also given for better understanding. What are the real-life applications of it? ∴ ∠ROS = $$\frac { 1 }{ 2 } (\angle QOS-\angle POS)$$. Telanagana SCERT Class 9 Math Solution Chapter 4 Lines and Angles Exercise 4.3 If ∠AOC + ∠BOE = 70° and ∠BOD = 40°, find ∠BOE and reflex ∠COE. ∴ b + a = 180° – 90° = 90° …(i) Question 1: (i) Angle: Two rays having a common end point form an angle. ∠ABL = ∠LBC and ∠MCB = ∠MCD But ∠POY = 90° [Given] But ∠BOD = 40° [Given] If you have any query regarding NCERT Solutions for Class 9 Maths Chapter 6 Lines and Angles Ex 6.1, drop a comment below and we will get back to you at the earliest. Lines and Angles Class 9 Extra Questions Very Short Answer Type. In figure, if x + y = w + ⇒, then prove that AOB is a line. Now, in ∆QRT, we have In figure, lines XY and MN intersect at 0. In figure, PQ and RS are two mirrors placed parallel to each other. We computed that the value of XYQ = 122°. ⇒ $$\frac { 1 }{ 2 }$$∠PRS = $$\frac { 1 }{ 2 }$$∠P + $$\frac { 1 }{ 2 }$$∠PQR Here, BE ⊥ CF and the transversal line BC cuts them at B and C, So, 2 = 3 (As they are alternate interior angles), So, AB CD alternate interior angles are equal). Question 1. In Fig. Ex 6.3 Class 9 Maths Question 1. Refer to the NCERT Solutions of Class 9 provided by our Experts below. (1) In the figure, we have CD and PQ intersect at F. ∴ ∠FGE + ∠GED = 180° [Co-interior angles] Ex 6.1 Class 9 Maths Question 1. ⇒ a = $$\frac { { 90 }^{ \circ } }{ 5 } \times 2\quad =\quad { 36 }^{ \circ }$$ = 36° we have ∠P + ∠PQS + ∠PSQ = 180° CBSE Previous Year Question Papers Class 10, CBSE Previous Year Question Papers Class 12, NCERT Solutions Class 11 Business Studies, NCERT Solutions Class 12 Business Studies, NCERT Solutions Class 12 Accountancy Part 1, NCERT Solutions Class 12 Accountancy Part 2, NCERT Solutions For Class 6 Social Science, NCERT Solutions for Class 7 Social Science, NCERT Solutions for Class 8 Social Science, NCERT Solutions For Class 9 Social Science, NCERT Solutions For Class 9 Maths Chapter 1, NCERT Solutions For Class 9 Maths Chapter 2, NCERT Solutions For Class 9 Maths Chapter 3, NCERT Solutions For Class 9 Maths Chapter 4, NCERT Solutions For Class 9 Maths Chapter 5, NCERT Solutions For Class 9 Maths Chapter 6, NCERT Solutions For Class 9 Maths Chapter 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Linear Equations in Two Variables, Chapter 5 Introduction to Euclids Geometry, Chapter 9 Areas of Parallelograms and Triangles, Download PDF of NCERT Solutions for Class 9 Maths Chapter 6 – Lines And Angles, NCERT Exemplar for class 9 Maths Chapter 6, Chapter 4 linear equation in two variables, Chapter 5 introduction to euclids geometry, Chapter 9 areas of parallelograms and triangle. or (∠AOC + ∠BOE) + ∠COE = 180° or 70° + ∠COE = 180° [ ∵∠AOC + ∠BOE = 70° (Given)] Here we have given NCERT Solutions for Class 9 Maths Chapter 6 Lines and Angles Ex 6.1. ) Class 9 Maths Chapter 6: Lines and Angles 91 an lines and angles class 9 solutions angle measures between 0° and,! 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